In a quadrilateral ABCD, the line segments bisecting 
C and D meet at E. Prove that A + B = 2 CED. 
Asked by Topperlearning User | 16th Aug, 2017, 02:17: PM
Expert Answer:
In 
DEC, 1+ 2 + CED = 180o (angle sum property of triangle)
CED = 180o – (1+ 2)
A + B+ C+D = 360o (angle sum property of quadrilateral)
DEC, 1+ 2 + CED = 180o (angle sum property of triangle)CED = 180o – (1+ 2)A + B+ C+D = 360o (angle sum property of quadrilateral)Answered by | 16th Aug, 2017, 04:17: PM
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