Asked by suchet_r | 21st Feb, 2010, 05:56: PM
First vessel contains 24 lit milk and 6 lit water, a total 30 lit of mixture.
Milk is 24/30 = 0.8 or 80% and water will be 20%.
Similarly for second mixture,
Milk is 15/25 = 0.6 or 60% and water will be 40%.
Let's say we should pick X lit from first vessel, and Y lit from second vessel.
Milk, that'll come with X lit of first mixture = 0.8X,
and that from Y lit of second miture = 0.6Y.
But this should to be total milk in the third mixture, which is 25 lit.
0.8X + 0.6Y = 25
8X + 6Y = 250 ...........(1)
Similarly for water,
0.2X + 0.4Y = 10
2X + 4Y = 100 ......(2)
Solving (1) and (2), we find.
X = 20 lit and Y = 15 lit.
Answered by | 21st Feb, 2010, 07:23: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number