JEE Class main Answered
if
Asked by ppavani198 | 19 Dec, 2018, 09:14: PM
Expert Answer
f(x) = (1+x)(1+x2)(1+x4)(1+x8)(1+x16)(1+x32)
log f(x) = log(1+x)+log(1+x2)+log(1+x4)+log(1+x8)+(1+x16)+log(1+x32)
By differentiation of above,
to get f '(x) at x=1/2, make the substitution in the above eqn.
Answered by Thiyagarajan K | 20 Dec, 2018, 05:04: PM
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