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CBSE Class 12-science Answered

If
 begin mathsize 20px style A equals 1 over straight pi open square brackets table row cell sin to the power of negative 1 end exponent open parentheses x straight pi close parentheses space space end cell cell tan to the power of negative 1 end exponent open parentheses x over straight pi close parentheses end cell row cell sin to the power of negative 1 end exponent open parentheses x over straight pi close parentheses space space end cell cell c o t to the power of negative 1 end exponent open parentheses πx close parentheses end cell end table close square brackets comma B equals 1 over straight pi open square brackets table row cell negative cos to the power of negative 1 end exponent open parentheses x straight pi close parentheses space space space end cell cell tan to the power of negative 1 end exponent open parentheses x over straight pi close parentheses end cell row cell sin to the power of negative 1 end exponent open parentheses x over straight pi close parentheses end cell cell negative tan to the power of negative 1 end exponent open parentheses πx close parentheses end cell end table close square brackets end style 
then find A-B
Asked by sunil2791 | 08 Jul, 2017, 07:31: PM
answered-by-expert Expert Answer
begin mathsize 16px style Please space check space if space there space is space any space condition space on space straight x. As space it space does space not space follow space the space condition sin to the power of negative 1 end exponent straight x plus cos to the power of negative 1 end exponent straight x equals straight pi over 2 space when for space straight x equals 1 space sin to the power of negative 1 end exponent straight pi straight x plus cos to the power of negative 1 end exponent πx rightwards double arrow sin to the power of negative 1 end exponent straight pi plus cos to the power of negative 1 end exponent straight pi space we space can space not space say space it space is space equal space to space straight pi over 2 Please space check space it space or space send space us space the space snapshot space of space the space question. After space computing space straight A minus straight B space you space will space get space open square brackets table row cell 1 over straight pi open square brackets sin to the power of negative 1 end exponent open parentheses πx close parentheses plus cos to the power of negative 1 end exponent open parentheses πx close parentheses close square brackets end cell 0 row 0 cell 1 over straight pi open square brackets cot to the power of negative 1 end exponent open parentheses πx close parentheses plus tan to the power of negative 1 end exponent open parentheses πx close parentheses close square brackets end cell end table close square brackets Consider comma sin to the power of negative 1 end exponent open parentheses πx close parentheses plus cos to the power of negative 1 end exponent open parentheses πx close parentheses Let comma space sin to the power of negative 1 end exponent open parentheses πx close parentheses equals straight theta......... left parenthesis straight i right parenthesis πx equals sinθ rightwards double arrow πx equals cos open square brackets straight pi over 2 minus straight theta close square brackets rightwards double arrow cos to the power of negative 1 end exponent open parentheses πx close parentheses equals straight pi over 2 minus straight theta........... left parenthesis ii right parenthesis Adding space left parenthesis straight i right parenthesis space and space left parenthesis ii right parenthesis rightwards double arrow sin to the power of negative 1 end exponent open parentheses πx close parentheses plus cos to the power of negative 1 end exponent open parentheses πx close parentheses equals straight pi over 2 if space open vertical bar πx close vertical bar less or equal than 1 rightwards double arrow open vertical bar straight x close vertical bar less or equal than 1 over straight pi Similarly space you space can space show space that space cot to the power of negative 1 end exponent open parentheses πx close parentheses plus tan to the power of negative 1 end exponent open parentheses πx close parentheses equals straight pi over 2 and space solve space further. end style
Answered by Sneha shidid | 12 Jul, 2017, 08:51: AM

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