Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 12-science Answered

<div>If</div> <div>&nbsp;<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=700629bc5370b1dcf06d2e7e8b77b49b.png" alt="begin mathsize 20px style A equals 1 over straight pi open square brackets table row cell sin to the power of negative 1 end exponent open parentheses x straight pi close parentheses space space end cell cell tan to the power of negative 1 end exponent open parentheses x over straight pi close parentheses end cell row cell sin to the power of negative 1 end exponent open parentheses x over straight pi close parentheses space space end cell cell c o t to the power of negative 1 end exponent open parentheses &pi;x close parentheses end cell end table close square brackets comma&#10;B equals 1 over straight pi open square brackets table row cell negative cos to the power of negative 1 end exponent open parentheses x straight pi close parentheses space space space end cell cell tan to the power of negative 1 end exponent open parentheses x over straight pi close parentheses end cell row cell sin to the power of negative 1 end exponent open parentheses x over straight pi close parentheses end cell cell negative tan to the power of negative 1 end exponent open parentheses &pi;x close parentheses end cell end table close square brackets end style" align="middle" />&nbsp;</div> <div>then find A-B</div>
Asked by sunil2791 | 08 Jul, 2017, 07:31: PM
Expert Answer
begin mathsize 16px style Please space check space if space there space is space any space condition space on space straight x.
As space it space does space not space follow space the space condition
sin to the power of negative 1 end exponent straight x plus cos to the power of negative 1 end exponent straight x equals straight pi over 2 space when
for space straight x equals 1 space
sin to the power of negative 1 end exponent straight pi straight x plus cos to the power of negative 1 end exponent πx
rightwards double arrow sin to the power of negative 1 end exponent straight pi plus cos to the power of negative 1 end exponent straight pi space we space can space not space say space it space is space equal space to space straight pi over 2
Please space check space it space or space send space us space the space snapshot space of space the space question.


After space computing space straight A minus straight B space you space will space get space open square brackets table row cell 1 over straight pi open square brackets sin to the power of negative 1 end exponent open parentheses πx close parentheses plus cos to the power of negative 1 end exponent open parentheses πx close parentheses close square brackets end cell 0 row 0 cell 1 over straight pi open square brackets cot to the power of negative 1 end exponent open parentheses πx close parentheses plus tan to the power of negative 1 end exponent open parentheses πx close parentheses close square brackets end cell end table close square brackets
Consider comma
sin to the power of negative 1 end exponent open parentheses πx close parentheses plus cos to the power of negative 1 end exponent open parentheses πx close parentheses
Let comma space sin to the power of negative 1 end exponent open parentheses πx close parentheses equals straight theta......... left parenthesis straight i right parenthesis
πx equals sinθ
rightwards double arrow πx equals cos open square brackets straight pi over 2 minus straight theta close square brackets
rightwards double arrow cos to the power of negative 1 end exponent open parentheses πx close parentheses equals straight pi over 2 minus straight theta........... left parenthesis ii right parenthesis
Adding space left parenthesis straight i right parenthesis space and space left parenthesis ii right parenthesis
rightwards double arrow sin to the power of negative 1 end exponent open parentheses πx close parentheses plus cos to the power of negative 1 end exponent open parentheses πx close parentheses equals straight pi over 2
if space open vertical bar πx close vertical bar less or equal than 1
rightwards double arrow open vertical bar straight x close vertical bar less or equal than 1 over straight pi
Similarly space you space can space show space that space cot to the power of negative 1 end exponent open parentheses πx close parentheses plus tan to the power of negative 1 end exponent open parentheses πx close parentheses equals straight pi over 2
and space solve space further.

end style
Answered by Sneha shidid | 12 Jul, 2017, 08:51: AM
CBSE 12-science - Maths
Asked by Gounshi | 01 Jun, 2020, 05:07: PM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by spd231624 | 04 May, 2019, 09:54: PM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by prashubh2000 | 25 Apr, 2019, 11:31: AM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by ppgm11patil | 29 Oct, 2018, 02:21: PM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by haroonrashidgkp | 31 Mar, 2018, 12:12: PM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 29 Apr, 2016, 07:51: AM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 28 Apr, 2016, 03:45: PM
ANSWERED BY EXPERT

Start your hassle free Education Franchisee and grow your business!

Know more
×