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If 2x+3y=12 and xy=6find the value of 8x³+27y³
Asked by Pratikshyapmuduli | 31 Jan, 2018, 10:44: PM Expert Answer

2x+3y=12

Xy =6

Find 8x^3+27y^3

2x+3y=12

Cubing both sides

(2x+3y)^3=12^3

(a+b)^3=a^3+b^3+3ab(a+b)=1728

8x^3+27y^3+3×2x×3y(2x+3y)=1728

8x^3+27y^3+18×6×12=1728

8x^3+27y^3+1296=1728

8x^3+27y^3= 432

Answered by Sneha shidid | 01 Feb, 2018, 07:42: AM
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