CBSE Class 9 Answered
If 2x+3y=12 and xy=6find the value of 8x³+27y³
Asked by Pratikshyapmuduli | 31 Jan, 2018, 10:44: PM
Expert Answer
2x+3y=12
Xy =6
Find 8x^3+27y^3
2x+3y=12
Cubing both sides
(2x+3y)^3=12^3
(a+b)^3=a^3+b^3+3ab(a+b)=1728
8x^3+27y^3+3×2x×3y(2x+3y)=1728
8x^3+27y^3+18×6×12=1728
8x^3+27y^3+1296=1728
8x^3+27y^3= 432
Answered by Sneha shidid | 01 Feb, 2018, 07:42: AM
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