How to solve the problem

Asked by sveluco | 30th Jun, 2018, 08:54: PM

Expert Answer:

begin mathsize 16px style open square brackets 8 to the power of 0 cross times 2 to the power of 0 close square brackets plus open square brackets 6 squared cross times open parentheses 1 over 6 close parentheses to the power of 4 close square brackets cross times open square brackets open parentheses 4 over 7 close parentheses to the power of 12 divided by open parentheses 4 over 7 close parentheses to the power of 10 close square brackets
1 cross times 1 plus 6 squared cross times 6 to the power of negative 4 end exponent cross times open parentheses 4 over 7 close parentheses to the power of 12 minus 10 end exponent
1 plus 6 to the power of 2 minus 4 end exponent cross times open parentheses 4 over 7 close parentheses squared
1 plus 6 to the power of negative 2 end exponent cross times open parentheses 4 over 7 close parentheses squared
1 plus 1 over 36 cross times 16 over 49
1 plus fraction numerator 4 over denominator 9 cross times 49 end fraction
1 plus 4 over 441
445 over 441 end style

Answered by Sneha shidid | 1st Jul, 2018, 01:57: PM