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Asked by manishasihag2002feb11 | 29 Feb, 2024, 10:02: AM
Let u = loga (x)
..................... (1)
In above expression, logae is constant .
By differentiating eqn.(1) , we get
f '(x) = logae × (1/u) × ( du/dx) .......................(2)
u = loga x = loge x × logae
du/dx = logae × (1/x)
By substituting du/dx , we rewrite eqn.(2) as
Answered by Thiyagarajan K | 29 Feb, 2024, 16:25: PM
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