how to factorise x^4+4x^3-x^2-16x-12using long division method
Asked by Anishma Joseph
| 2nd Jul, 2013,
10:47: PM
Expert Answer:
Let f(x)= x^4+4x^3-x^2-16x-12
Clearly, (x+1), (x+2) are factors of of f(x). (Since, f(-1)=f(-2)=0)
Hence, (x+1).(x+2)=x^2+3x+2 is a factor of f(x).
Now, divide f(x) by x^2+3x+2.
The remainder will be 0 and quotient will be x^2 + x - 6.
Now, x^2 + x - 6 = (x+3)(x-2)
Hence, f(x) = (x+1) (x+2) (x+3) (x-2)
Answered by
| 2nd Jul, 2013,
11:08: PM
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