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How many total stereoisomers ( Both geometrical and optical) are present for this compound, which is known as shikimic acid?
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Asked by sumayiah2000 | 17 Apr, 2019, 11:17: AM
answered-by-expert Expert Answer
T o t a l space o f space 16 space s t e r e o i s o m e r s space c a n space b e space s e e n space i n space t h e space g i v e n space m o l e c u l e. bold italic R bold italic e bold italic a bold italic s bold italic o bold italic n space colon space 3 space c h i r a l space c e n t e r s space s e e n space c l e a r l y space left parenthesis C to the power of asterisk times minus O H right parenthesis space s o space b e c a u s e space o f space t h e m comma space 2 cubed space equals 8 space i s o m e r s D o u b l e space B o n d space equals space 2 space left parenthesis E divided by Z right parenthesis space plus space 6 space semicolon space 3 O H thin space g r o u p s space W i l l space g i v e space d i f f e r e n t space left parenthesis E divided by Z right parenthesis space f o r m s
Answered by Sumit Chakrapani | 19 Apr, 2019, 02:38: AM

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