Hi

1)Please answerthe following question

2)please explain the cocept,logic and the thought process to solve this question

3)please tell how much time a 7th class student should take to solve this in any competitive exam?

Asked by Bovanghai | 3rd May, 2019, 06:01: PM

Expert Answer:

37 over 13 equals 2 plus fraction numerator 1 over denominator straight a plus begin display style fraction numerator 1 over denominator straight b plus begin display style 1 over straight c end style end fraction end style end fraction
fraction numerator begin display style 37 end style over denominator begin display style 13 end style end fraction minus 2 equals fraction numerator begin display style 1 end style over denominator begin display style straight a plus fraction numerator straight c over denominator begin display style bc plus 1 end style end fraction end style end fraction
Taking space LCM
11 over 13 equals fraction numerator bc plus 1 over denominator abc plus straight a plus straight c end fraction
since space fraction numerator begin display style 11 end style over denominator begin display style 13 end style end fraction space can apostrophe straight t space be space reduced space further comma
so
bc plus 1 equals 11.... left parenthesis 1 right parenthesis
abc plus straight a plus straight c equals 13... left parenthesis 2 right parenthesis
in space order space to space solve space above space equation space we space need space one space more space equation.
so space best space case space is space to space check space for space correct space ans space by space substituting space options

Answered by Arun | 4th May, 2019, 09:25: AM