CBSE Class 7 Answered
Find the value of m when
[3(m-7)]3=1
Asked by | 05 Mar, 2014, 06:18: PM
Expert Answer
We know the law of exponent, (ax)y = axy
Hence [3(m-7)]3=1
=> 3(3m-21)=30 (Since a0 = 1)
Equating the powers on both sides,
=> 3m- 21 = 0
or m = 7.
Answered by | 06 Mar, 2014, 09:55: AM
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