# Gujarat Class 10 Answered

**Find the sum of all three digit natural numbers divisible by 3**

Asked by kvdudhaiya | 16 Jan, 2019, 14:08: PM

Expert Answer

sum = ( 3+6+9+.......+999) = 3×(1+2+3.....+333)

sum = ( 3×333×334)/2 = 3×333×167 = 166833

( sum of n natural numbers ,i.e, 1+2+3 .....n, is n(n+1)/2 )

Answered by Thiyagarajan K | 16 Jan, 2019, 15:01: PM

## Concept Videos

Gujarat 10 - Maths

Asked by gourimahesh | 24 Nov, 2021, 10:28: AM

ANSWERED BY EXPERT

Gujarat 10 - Maths

Asked by mehta2804ansh | 22 Jun, 2021, 14:38: PM

ANSWERED BY EXPERT

Gujarat 10 - Maths

Asked by edusimple_guj_teacher | 23 May, 2020, 10:58: AM

ANSWERED BY EXPERT

Gujarat 10 - Maths

Asked by mangalkalyani1983 | 07 Jun, 2019, 15:53: PM

ANSWERED BY EXPERT

Gujarat 10 - Maths

Asked by pandharinath.624 | 10 Mar, 2019, 23:53: PM

ANSWERED BY EXPERT

Gujarat 10 - Maths

Asked by tanishquabansal2195 | 14 Feb, 2019, 18:20: PM

ANSWERED BY EXPERT

Gujarat 10 - Maths

Asked by kenilmonpara24 | 20 Jan, 2019, 17:58: PM

ANSWERED BY EXPERT

Gujarat 10 - Maths

Asked by kvdudhaiya | 16 Jan, 2019, 14:08: PM

ANSWERED BY EXPERT

Gujarat 10 - Maths

Asked by namupatel154 | 31 Dec, 2018, 07:38: AM

ANSWERED BY EXPERT