Foundation Class 10 Answered
find the sum of 70+68+66+........+40
Asked by arushanaseer | 07 May, 2024, 01:08: PM
Expert Answer
Above sum is sum of terms of arithmetic progression (A.P)
First term of A.P = 70
Common difference = -2
Last term 40 is
tn = a + (n-1)d = 40
70 + (n-1)(-2) = 40
n = 16
Sum of 40 temrs is
Sn = (n/2) [ 2a + (n-1) d ] = (16/2) [ 2(70) + (16-1)(-2) ] = 880
Answered by Thiyagarajan K | 07 May, 2024, 03:00: PM
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Foundation 10 - Maths
Asked by arushanaseer | 07 May, 2024, 01:08: PM
ANSWERED BY EXPERT
