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CBSE Class 12-science Answered

<div><img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=e11eac0a841a96ac0be28c6ff91eaa41.png" alt="integral square root of sin to the power of negative 1 end exponent end root left parenthesis x minus a right parenthesis space d x&#10;integral top enclose square root of sin to the power of negative 1 end exponent left parenthesis x plus a right parenthesis end root end enclose" align="middle" /></div> <div>FIND THE INTEGRAL OF THE ABOVE QUESTION.</div> <div>&nbsp;</div>
Asked by modi72879 | 25 Oct, 2017, 09:43: AM
Expert Answer
begin mathsize 16px style integral square root of sin to the power of negative 1 end exponent open parentheses straight x minus straight a close parentheses space end root dx
Put space straight x minus straight a equals straight t
dx equals dt
rightwards double arrow integral square root of sin to the power of negative 1 end exponent straight t space end root dt
Put space sin to the power of negative 1 end exponent straight t space space equals space straight y
siny space equals space straight t rightwards double arrow sin squared straight y equals straight t squared
rightwards double arrow cosydy equals dt
integral square root of straight y space cosy space dy
Using space integral space by space parts space where space straight u equals square root of straight y space and space straight v equals cosy
integrate space further.

Second space question space you space can space solve space using space the space same space method space explained space above. end style
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