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CBSE Class 12-science Answered

<div><img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=e11eac0a841a96ac0be28c6ff91eaa41.png" alt="integral square root of sin to the power of negative 1 end exponent end root left parenthesis x minus a right parenthesis space d x&#10;integral top enclose square root of sin to the power of negative 1 end exponent left parenthesis x plus a right parenthesis end root end enclose" align="middle" /></div> <div>FIND THE INTEGRAL OF THE ABOVE QUESTION.</div> <div>&nbsp;</div>
Asked by modi72879 | 25 Oct, 2017, 09:43: AM
Expert Answer
begin mathsize 16px style integral square root of sin to the power of negative 1 end exponent open parentheses straight x minus straight a close parentheses space end root dx Put space straight x minus straight a equals straight t dx equals dt rightwards double arrow integral square root of sin to the power of negative 1 end exponent straight t space end root dt Put space sin to the power of negative 1 end exponent straight t space space equals space straight y siny space equals space straight t rightwards double arrow sin squared straight y equals straight t squared rightwards double arrow cosydy equals dt integral square root of straight y space cosy space dy Using space integral space by space parts space where space straight u equals square root of straight y space and space straight v equals cosy integrate space further. Second space question space you space can space solve space using space the space same space method space explained space above. end style
Answered by Sneha shidid | 14 Dec, 2017, 04:49: PM
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