CBSE Class 12-science Answered
find the equation of the tangents drawn from the point (1,2) to the curve
Asked by | 08 Jan, 2009, 11:59: AM
Expert Answer
differenciating the eqn of curve with respect to y
2y - 6x2dx/dy -4 =o
At (1,2)
dx/dy=0
So tangent is parellel to y axis
Equation of a line parallel to y axis is given by
x =c
(1,2) lies on the tangent
x =1 is the equation of the tangent
Answered by | 30 Jan, 2009, 01:05: AM
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