find the equation of the tangents drawn from the point (1,2) to the curve

Asked by  | 8th Jan, 2009, 11:59: AM

Expert Answer:

differenciating the eqn of curve with respect to y

2y - 6x2dx/dy -4 =o

At (1,2)

dx/dy=0

So tangent is parellel to y axis

Equation of a line parallel to y axis is given by

x =c

(1,2) lies on the tangent

x =1 is the equation of the tangent

Answered by  | 30th Jan, 2009, 01:05: AM

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