JEE Class main Answered
find kinetic energy of rocket
Asked by ashutosharnold1998 | 21 Jan, 2020, 00:47: AM
Expert Answer
Mechanical energy of satellite on Earth surface, MEe = (1/2)Mu2 - ( G Me M )/R .............................(1)
After ejecting a rocket of mass (M/10), Mechanical energy MEO of satellite in an orbit of radius 2R is given by
MEO = - [ G Me (9/10)M ] / [ 2(2R) ] = -(9/40) ( G Me M )/R ......................(2)
Potential energy PE of ejected rocket is given by, PE = - [ G Me (1/10)M ] / (2R) = -(1/20) ( G Me M )/R .....................(3)
Hence kinetic energy KE of Rocket, KE = MEe - MEO - PE .........................(4)
Using eqn.(1), eqn.(2) and eqn.(3), we get, KE = (1/2)Mu2 - ( G Me M )/R + (9/40) ( G Me M )/R + (1/20) ( G Me M )/R
Kinetic energy of rocket, KE = M { (u2 / 2 ) - [ ( 21 G Me ) / (40R) ] }
Answered by Thiyagarajan K | 22 Jan, 2020, 09:38: AM
Application Videos
Concept Videos
JEE main - Physics
Asked by swapnanemuturi | 23 Jul, 2024, 21:21: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by chetanjakhar86 | 20 Jul, 2024, 23:39: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by tannujangra726 | 14 Jul, 2024, 22:02: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by senapareddirajeshkumar8 | 13 Jul, 2024, 16:23: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by nidhikalluthattu | 11 Jul, 2024, 20:00: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by ymydheli | 10 Jul, 2024, 19:20: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by manishkanna555 | 07 Jul, 2024, 10:25: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by prachitipatil146 | 05 Jul, 2024, 20:34: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by akshara9071 | 04 Jul, 2024, 18:50: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by ammuc990 | 04 Jul, 2024, 09:51: AM
ANSWERED BY EXPERT