ICSE Class 7 Answered
find 3 consecutive odd numbers such that 3 times the least number is added to double the greatest number and the result is 333
Asked by shirdhankarc | 09 Jan, 2019, 19:19: PM
Expert Answer
Let three consecutive odd numbers be 2n + 1, 2n + 3, 2n + 5
Where least number is 2n + 1 and largest number is 2n + 5
According to the question,
3(2n +1) + 2(2n + 5) = 333
Simplifying we get
n = 32
Hence, the numbers are 2n + 1 = 65, 2n + 3 = 67 and 2n + 5 = 69
Answered by Sneha shidid | 10 Jan, 2019, 10:59: AM
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