NEET Class neet Answered
explain
Asked by adititiwari601 | 24 Jun, 2022, 21:02: PM
Expert Answer
Let us consider the first stone is dropped when balloon is at a position A . Let vA be its velocity.
After 2 seconds the balloon reaches the position B and its speed at B is vB
vB = vA + ( a × t )= vA + (0.2 × 2 ) = vA + 0.4 ......................................(1)
where a = 0.2 m/s2 is acceleration of balloon
In 2 seconds , balloon has travelled a distance h that is determined from following equation
vB2 = vA2 + ( 2 a h )
h = ( vB2 - vA2 ) / ( 2 a ) = [ ( vA+0.4 )2 - vA2 ] / ( 2 × 0.2 )
h = ( 0.8 vA + 0.16 ) / 0.4 = 2 vA + 0.4 ...................................(2)
At position A , when a stone is dropped means , stone moves upwards with speed vA
Similarly, At position B , when a stone is dropped means , stone moves upwards with speed vB
If it is required to find the distances between two stones 1.5 s after dropping second stone,
then stone dropped at A has travelled 3.5 s and stone dropped at B has travelled only 1.5 s.
Let us find the distance by taking positio-A as reference point
If hA is the distance travelled by first stone, then
hA = ( vA t ) - [ (1/2) g t2 ] = ( 3.5 vA ) - [ 4.9 × 3.5 × 3.5 ]
hA = ( 3.5 vA ) - 60.025
If hB is the distance travelled by second stone, then
hB = h + ( vB t ) - [ (1/2) g t2 ]
Let us substitute h from eqn.(2) and vB from eqn.(1)
hB = ( 2 vA + 0.4 ) + [ 1.5 ( vA +0.4) ] - [ 4.9 × 1.5 × 1.5 ]
hB = ( 3.5 vA ) - 10.025
Distance between two stones is calculated as
hB - hA = ( 3.5 vA ) - 10.025 - [ ( 3.5 vA ) - 60.025 ]
hB - hA = 50 m
Answered by Thiyagarajan K | 24 Jun, 2022, 23:34: PM
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