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CBSE Class 10 Answered

Evaluate
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Asked by agrimt1212 | 17 Jul, 2021, 17:39: PM
answered-by-expert Expert Answer
 
begin mathsize 18px style L e t space space x space equals space 2 to the power of log subscript 2 square root of 2 end subscript superscript 5 end exponent end style
begin mathsize 14px style log subscript 2 square root of 2 end subscript superscript 5 space equals space fraction numerator log subscript 10 superscript 5 over denominator log subscript 10 superscript 2 square root of 2 end superscript end fraction space equals space fraction numerator 0.699 over denominator 0.451 end fraction equals space 1.55 end style
begin mathsize 14px style x space equals space 2 to the power of 1.55 end exponent end style
log(x) = 1.55 × log(2) = 1.55 × 0.3010 = 0.466
 
x = Antilog (0.466) = 2.928
 
Answered by Thiyagarajan K | 17 Sep, 2021, 18:58: PM

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