Evaluate: ??e^x (tanx-logcosx) ? dx Sir, please be kind enough to tell me whether -log|cosx|=log?secx
Asked by Manoj
| 29th Mar, 2013,
06:29: AM
Expert Answer:
Yes, -log|cosx| = log |cosx^-1| = log|1/cosx| = log|secx|
Answered by
| 29th Mar, 2013,
07:24: AM
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