Evaluate: ??e^x (tanx-logcosx) ? dx Sir, please be kind enough to tell me whether -log|cosx|=log?secx

Asked by Manoj | 29th Mar, 2013, 06:29: AM

Expert Answer:

Yes, -log|cosx| = log |cosx^-1| = log|1/cosx| = log|secx|

Answered by  | 29th Mar, 2013, 07:24: AM

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