CBSE Class 10 Answered
Evaluate cos48°cos42°–sin48°sin42°
Asked by Maharanam446 | 22 Jan, 2020, 13:21: PM
Expert Answer
cos48°cos42° – sin48°sin42°
= cos(90° - 42°)cos(90° - 48°) – sin48°sin42°
= sin48°sin42° - sin48°sin42° .... cos(90° - θ) = sinθ
= 0
Answered by Yasmeen Khan | 22 Jan, 2020, 17:04: PM
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