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CBSE Class 10 Answered

Evaluate cos48°cos42°–sin48°sin42°
Asked by Maharanam446 | 22 Jan, 2020, 01:21: PM
answered-by-expert Expert Answer
cos48°cos42° – sin48°sin42°
cos(90° - 42°)cos(90° - 48°) – sin48°sin42°
= sin48°sin42° - sin48°sin42°               .... cos(90° - θ) = sinθ
= 0 
Answered by Yasmeen Khan | 22 Jan, 2020, 05:04: PM

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