DIFFERTIATE

Asked by | 8th Jun, 2008, 09:13: PM

Expert Answer:

log_a b log_b c = log_a c

using this identity loge10 = log₁₀10 / log₁₀ e = 1/ log₁₀ e

differentiating it w.r.t log₁₀ e will give us -1/ (log₁₀ e)²

Answered by | 12th Sep, 2008, 03:30: AM

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