?cos4x+1/cotx-tanx dx=a cos 4x+b,find a
Asked by abhi patel | 17th May, 2012, 10:06: PM
Expert Answer:
On Solving the equation we get , {cos4x+1}/{cotx - tanx} = (2cos22x)(sinx.cosx)/(cos2x - sin2x) = cos2x.sin2x = sin4x/2
On Integrating we get , -cos4x/8 + C
a = -1/8
Answered by | 18th May, 2012, 01:14: PM
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