construct triangle ABC so that BC=6 cm ,angle BAC= 40 and the length of the median drawn from A to BC is 7 cm .How to proceed?please tell and also write steps of construction.Thank you

Asked by  | 5th Dec, 2013, 07:56: PM

Expert Answer:

Steps of construction;

i. Draw a line segment BC= 6 cm.

ii. Below BC, construct angle CBE = 40o.

iii. Draw the perpendicular bisector MN of BC, intersecting BC at D

iv. Draw Bo perpendicular to BE, intersecting MN at O.

v. Draw a circle with O as centre and radius equal to OB.

vi. With D as centre and radius equal to 7 cm draw an arc, intersecting the circle in A.

vii. Join AB and AC.

Thus, we obtain triangle ABC.

Answered by  | 7th Dec, 2013, 03:31: PM

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