Construct a triangle PQR with QR=7cm ,angle Q=75 degrees and PQ-PR=3cm
Asked by | 28th Nov, 2012, 10:59: PM
STEP I: Draw a line QR of length 7 cm and contruct angle XQR=75°
STEP II:Cut a line segment QM=3 cm(PQ-PR)
STEP III: Join M and R and draw the Perpendicular Bisector of MR and the point at which it cuts QX will be P.
STEPIV: join P and R and the triangle PQR is Constructed.
Answered by | 29th Nov, 2012, 11:18: PM
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