Construct a triangle PQR with QR=7cm ,angle Q=75 degrees and PQ-PR=3cm

Asked by  | 28th Nov, 2012, 10:59: PM

Expert Answer:

STEP I: Draw a line QR of length 7 cm and contruct angle XQR=75°
STEP II:Cut a line segment QM=3 cm(PQ-PR)
STEP III: Join M and R and draw the Perpendicular Bisector of MR and the point at which it cuts QX will be P.
STEPIV: join P and R and the triangle PQR is Constructed.

Answered by  | 29th Nov, 2012, 11:18: PM

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