CBSE Class 9 Answered
Construct a ABC in which BC = 5.7 cm B = 30o and AB - AC = 3 cm.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
Steps of Construction :
1. Draw the base BC=5.7 cm and at point B make an angle
say XBC = 300.
2. Cut the line segment BD equal to AB - AC = 3 cm from
ray BX.
3. Join DC and draw the perpendicular bisector of DC.
4. Let it intersect BX at a point A. Join AC.
ABC is the required triangle.
Answered by | 04 Jun, 2014, 03:23: PM
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