Ask a Doubt
Request a call back

Join NOW to get access to exclusive study material for best results

ICSE Class 10 Answered

calculate ionization energy for second orbit from where the electron is removed.
 
please solve the question step by step.
Asked by amulya.kr01 | 21 Feb, 2016, 11:23: AM
answered-by-expert Expert Answer
begin mathsize 14px style The space ionization space energy space is space the space energy space required space to space remove space an space electron space from space straight a space particular space orbit space of space an space atom. Consider space Hydrogen space atom. The space ionization space energy space is space given space as straight E equals fraction numerator 13.6 straight Z squared over denominator straight n squared end fraction So comma space if space an space electron space is space to space be space removed space from space the space second space orbit space for space hydrogen space atom comma space then space we space have straight Z equals 1 space and space straight n equals 2 therefore straight E equals 13.6 cross times 1 squared over 2 squared equals fraction numerator 13.6 over denominator 4 end fraction equals 3.4 space eV Hence comma space an space energy space of space 3.4 space eV space has space to space be space imparted space to space remove space the space electron space from space the space second space orbit. end style
Answered by Romal Bhansali | 22 Feb, 2016, 12:36: PM
Multiple Choice Questions Practice Test
My Class Videos Tests ₹ Plans Ask a Doubt
Get Latest Study Material for Academic year 24-25 Click here
×