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Asked by | 25th Aug, 2008, 09:45: PM
Expert Answer:
no such matrix exits
because for a mtrix A and its inverse A-1 we have following identity
A*A-1 = I where I is identity matrix
so |A| |A-1| = 1 ........(1)
if A-1 is a null matrix then |A-1| wil be zero then (1) will not be satisfied
Answered by | 11th Sep, 2008, 01:03: PM
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