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Asked by  | 25th Aug, 2008, 09:45: PM

Expert Answer:

no such matrix exits

because for a mtrix A and its inverse A-1 we have following identity

A*A-1 = I  where I is identity matrix

so |A| |A-1| = 1 ........(1)

if A-1 is a null matrix then |A-1| wil be zero then (1) will not be satisfied

Answered by  | 11th Sep, 2008, 01:03: PM

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