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An unknown metal of mass 192 g heated to a temperature of 100ºC was immersed into a brass calorimeter of mass 128 g containing 240 g of water a temperature of 8.4ºC Calculate the specific heat of the unknown metal if water temperature stabilizes at 21.5ºC (Specific heat of brass is 394 J kg–1 K–1) (1) 1232 J kg–1 K–1 (2) 458 J kg–1 K–1 (3) 654 J kg–1 K–1 (4) 916 J kg–1 K–1
Asked by swathibinoj | 02 Apr, 2019, 20:36: PM
answered-by-expert Expert Answer
Heat loss by metal = mass×sp.heat×(Temperature difference) = 192×10-3×s×(100-21.5) = 15.072×s Joule
 
where s is specific heat of unknown metal
 
Heat gain by calorimeter + water = 128×10-3 × 394 ×(21.5-8.4) + 240×10-3 × 4200 × (21.5 - 8.4) = 13865 Joule
 
specific heat s = 13865/15.072 ≈ 920 J/(kgK)
Answered by Thiyagarajan K | 04 Apr, 2019, 11:53: AM

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