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An object 6 cm high , is placed at a distance of 36 cm from a diverging lens of focal length 12 cm . CALCULATE the position and size of image and also draw the RAY DIAGRAM ? ( PLS DEAR EXPERTS ANS URGENTLY )
Asked by Vikas | 10 Aug, 2016, 11:45: PM
answered-by-expert Expert Answer
 
begin mathsize 12px style Given space that space straight h space equals space 6 space cm comma space straight u space equals space minus 36 space cm space and space straight f space equals space minus 12 space cm Using space the space lens space formula comma space we space get 1 over straight v minus 1 over straight u equals 1 over straight f 1 over straight v minus fraction numerator 1 over denominator negative 36 end fraction equals negative 1 over 12 1 over straight v equals negative 1 over 9 straight v space equals space minus 9 space cm Magnification comma space straight m space equals space straight v over straight u equals fraction numerator negative 9 over denominator negative 36 end fraction rightwards arrow straight m space equals space 0.25 space cm Also comma space straight m space equals space fraction numerator straight h over denominator straight h apostrophe end fraction rightwards arrow straight h apostrophe space equals space straight m cross times straight h space equals space 0.25 space cross times space 6 space cm rightwards arrow straight h apostrophe space equals 1.5 space cm space Thus comma space the space image space formed space is space diminished comma space erect space and space virtual space in space nature. It space is space formed space beteen space the space focus space and space the space optical space centre. end style
Answered by Yashvanti Jain | 11 Aug, 2016, 12:32: PM

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