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An ideal gas is enclosed in a container of volume V at a pressure P. It is being pumped out of the container by using a pump with stroke volume v. What is final pressure in container after n-stroke of the pump?— (1) P(V/V+v)^n, (2) PV/(V-v)^n, (3) PV^n/v^n, (4) P(V/V-v)^n
Asked by patra04011965 | 20 Jun, 2019, 15:39: PM
answered-by-expert Expert Answer
Let us assume m number of moles of ideal gas present in the container of volume V initially 
 
at temperature T and pressure P.
 
we have,  P V = m R T  .............................(1)
 
During first stroke, volume v is pumped out . Number of moles left out in container  =  m(V-v)/V.
 
after the first stroke, pressure decrases to P1 , volume of gas in the container remains constant.
Also we assume this is isothermal process
 
hence now we have,   P1 V = [ m(V-v)/V ] R T ..................(2)
 
By dividing eqn.(2) by eqn.(1), we get, ( P1 / P ) = (V-v)/V = [ 1 - (v/V) ]
 
Hence after first stroke, pressure P1 = P [ 1 - (v/V) ] .............................(3)
 
In same manner, we get the pressure P2 after second stroke as,  P2 = P1[ 1 - (v/V) ] .....................(4)
 
using eqn.(3), we rewrite eqn.(4) as,  P2 = P [ 1 - (v/V) ]2
 
After n stroke,  pressure in the container,   Pn = P [ 1 - (v/V) ]n = P [ (V-v)/V ]n
 
Answered by Thiyagarajan K | 20 Jun, 2019, 16:59: PM

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