CBSE Class 10 Answered
An erect image 3 time the size of object is formed concave mirror whose radius of curvature 36cm find the position object
Asked by Srj9887780 | 23 Sep, 2018, 09:58: AM
Expert Answer
Let u be the mirror to object distance and v be the mirror to image distance.
focal distance f of mirror is given by, f = R/2 , where R is radius of curvature. hence f = 36/2 = 18 cm
magnification of image = -v/u = 3
-ve sign indicates image is inverted. hence v = 3u, both v and u are same sign.
we have mirror equation, (1/v) + (1/u) = 1/f ...................(1)
hence 
................................(2)
................................(2)solving eqn.(2) for u, u = 24 cm.
Answered by Thiyagarajan K | 23 Sep, 2018, 10:50: AM
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