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CBSE Class 10 Answered

An erect image 3 time the size of object is formed concave mirror whose radius of curvature 36cm find the position object
Asked by Srj9887780 | 23 Sep, 2018, 09:58: AM
answered-by-expert Expert Answer
Let u be the mirror to object distance and v be the mirror to image distance.
 
focal distance f of mirror is given by,  f = R/2 , where R is radius of curvature. hence f = 36/2 = 18 cm
 
magnification of image = -v/u = 3
 
-ve sign indicates image is inverted. hence v = 3u, both v and u are same sign.
 
we have mirror equation, (1/v) + (1/u) = 1/f ...................(1)
 
hence begin mathsize 12px style fraction numerator 1 over denominator 3 u end fraction plus 1 over u space equals space 1 over 18 end style ................................(2)
solving eqn.(2) for u,  u = 24 cm.
Answered by Thiyagarajan K | 23 Sep, 2018, 10:50: AM
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