Request a call back

An erect image 3 time the size of object is formed concave mirror whose radius of curvature 36cm find the position object
Asked by Srj9887780 | 23 Sep, 2018, 09:58: AM
Let u be the mirror to object distance and v be the mirror to image distance.

focal distance f of mirror is given by,  f = R/2 , where R is radius of curvature. hence f = 36/2 = 18 cm

magnification of image = -v/u = 3

-ve sign indicates image is inverted. hence v = 3u, both v and u are same sign.

we have mirror equation, (1/v) + (1/u) = 1/f ...................(1)

hence ................................(2)
solving eqn.(2) for u,  u = 24 cm.
Answered by Thiyagarajan K | 23 Sep, 2018, 10:50: AM
CBSE 10 - Science
Asked by muskanprayagraj78 | 26 Feb, 2024, 05:44: PM
CBSE 10 - Science
Asked by kmannatpreet4 | 21 Feb, 2024, 07:34: PM
CBSE 10 - Science
Asked by umaambiger87 | 08 Feb, 2024, 03:28: PM
CBSE 10 - Science
Asked by pvasanth3573 | 07 Feb, 2024, 10:13: PM
CBSE 10 - Science
Asked by samirankarmakar2702 | 07 Feb, 2024, 09:59: PM
CBSE 10 - Science
Asked by sakshikatewa0 | 07 Feb, 2024, 03:06: PM