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Asked by vaibhavrao.0105 | 17 May, 2019, 06:31: AM
answered-by-expert Expert Answer
ΔP0 = force/area   = ;      Dimensions of ΔP0 = M L T-2 / L2 = M L-1 T-2
 
Since arguments of cosine function do not have any dimension, dimension of constant B is L-1
 
Hence dimensions of ΔP0 × B  is  M L-1 T-2 × L-1  =  M L-2 T-2
Answered by Thiyagarajan K | 17 May, 2019, 09:58: AM
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