A right triangle with sides 6cm,8cm, and 10cm is revolved about the side 8 cm.Find the volume and the curved surface of the cone so formed.(take π=3.14)

Asked by Kanwaranita10 | 27th Dec, 2019, 01:07: PM

Expert Answer:

 
Since, the given right angled triangle is revolved about the side 8 cm, it will form a Cone of radius 6cm and height 8cm.
 
Volume of a cone = 1/3∏r2h = 1/3×3.14×6×6×8 = 301.44 cm3
 
Curved Surface area of a cone =∏rl       .... (i)
We know that,
l2 = r2 + h2 = 62 + 82 = 36 + 64 = 100
→ l = 10 cm
Substitute the value of l in (i), we get

Curved Surface area of a cone = 3.14 × 6 × 10 = 188.4 cm2 

Answered by Yasmeen Khan | 27th Dec, 2019, 04:25: PM