ICSE Class 8 Answered
A regular pentagon ABCDE and a square ABFG are formed on opposite side of AB find angle BCF
Asked by prachibadal11 | 25 Jul, 2019, 08:22: PM
Expert Answer
Now angle FBA = 90
angle ABC = 108
so by sum of all angles at a point
angle FBC = 162
also triangle FBC is isosceles triangle so
angle BFC = 1/2(180 - angle FBC)
angle BFC = 9 degree
Answered by Arun | 27 Jul, 2019, 10:40: AM
ICSE 8 - Maths
Asked by prachibadal11 | 25 Jul, 2019, 08:22: PM
ANSWERED BY EXPERTICSE 8 - Maths
Asked by Cl_narayan | 14 Jul, 2019, 08:48: AM
ANSWERED BY EXPERT
