A question from your episode...
Asked by bhaipandu | 21st Mar, 2010, 09:16: PM
In the episode we have aplied Fundamental theorem of Arithmetic and not Euclid's theorem.
Greatest number of 6 digits = 999999
we need a number which is divisible by all of 24, 15 and 36
Number which is divisible by 24,15 and 36 is also divisible by the L.C.M. of 24, 15, and 36.
The prime factorization of 24 = 23x3
36 = 32 x 22
L.C. M. = Product of greatest power of each prime factor involved in numbers=8x9x5 = 360
now 999999 is not divisible by 360
is not divisible by 360
Hence required number = 999999 – remainder when 999999 divided by 360
Required No is 999999 –279 = 999720.
Answered by | 22nd Mar, 2010, 10:22: AM
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