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A particle is performing SHM.its total energy is E.When displacement is half of its amplitude, its Kinetic energy will be?
Asked by vishalnain161988 | 23 Sep, 2019, 08:02: PM
Expert Answer
Kinetic energy = Total Energy - Potential energy
Potential energy U of particle exhibiting SHM is given by, U = (1/2) k x2 = (1/2) m ω2 x2 ............... (1)
where m is mass of particle, ω is angular frequency and x is displacement
If displacement is half the amplitude A, then potential energy U = (1/2) m ω2 (A/2)2 = (1/8) m ω2 A2 ............(2)
Kinetic energy = E - (1/8) m ω2 A2
Answered by Thiyagarajan K | 23 Sep, 2019, 11:05: PM
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