Request a call back

A particle is performing SHM.its total energy is E.When displacement is half of its amplitude, its Kinetic energy will be?
Asked by vishalnain161988 | 23 Sep, 2019, 08:02: PM
Kinetic energy = Total Energy - Potential energy

Potential energy U of particle exhibiting SHM  is given by,   U = (1/2) k x2 = (1/2) m ω2 x2 ............... (1)

where  m is mass of particle, ω is angular frequency and x is displacement

If displacement is half the amplitude A, then potential energy U = (1/2) m ω2 (A/2)2 = (1/8) m ω2 A2 ............(2)

Kinetic energy = E - (1/8) m ω2 A2
Answered by Thiyagarajan K | 23 Sep, 2019, 11:05: PM

## Application Videos

JEE main - Physics
Asked by arnendubiswas5 | 28 May, 2024, 09:27: AM
JEE main - Physics
Asked by lalamsurya41 | 27 May, 2024, 10:37: AM
JEE main - Physics
Asked by yash4518chavan | 25 May, 2024, 05:58: PM
JEE main - Physics
Asked by yashu22022006 | 25 May, 2024, 09:13: AM
JEE main - Physics
Asked by rishisalunke678 | 24 May, 2024, 04:48: PM
JEE main - Physics
Asked by pataiyalalit02 | 19 May, 2024, 04:53: PM