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ICSE Class 10 Answered

A man is x² old and his son is x years old. if the man lives to the age of 18x his son then be x² years old. find the present age of the man and the boy.
Asked by dwivedi_anand | 27 Nov, 2018, 04:14: PM
answered-by-expert Expert Answer
Present age of father = x2 years.
Present age of sun = x years
 
if father lives upto age 18x years means, number of years from present time = (18x -x2 ) years
 
age of son after (18x - x2) years = x+18x-x2 = 19x - x2 = x2 .................(1)
eqn. (1) is rewritten as, 19x -2x2 = 0   or 19 - 2x = 0    or   x = 9.5 years
 
Hence at present, son is 9.5 years old and father is 90.25 years old.
 
Though this question is solved as per the given information, the numbers are not reasonable.
we are getting fraction in present age of sun. Even if we accept the fraction,  fathers age is worked out as 90.25 years.
Father is expected to live upto 171 years.
 
Suppose this same question is changed as given below :
 
A man is x2 years old and his son is x years old now. If the man lives upto  the age of 11x  years his son is then x2 years old.
Find the present age of father and son
 
we will solve this modified question as earlier
 
Present age of father = x2 years.
Present age of sun = x years
 
 
if father lives upto age 11x years means, number of years from present time = (11x -x2 ) years
 
age of son after (11x - x2) years = x+11x-x2 = 12x - x2 = x2 .................(2)
eqn. (2) is rewritten as, 12x -2x2 = 0   or 12 - 2x = 0    or   x = 6 years
 
Hence at present, son is 6 years old and father is 36 years old.
 
when father's age is 11×6  = 66 years means, 30 years after the presnt time.
At that time son's age is 6+30 = 36 years.
 
Everything looks reasonable.
Answered by Thiyagarajan K | 28 Nov, 2018, 04:56: AM
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