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A constant force acts on a body of mass 0.9kg at rest for 10s. If the body moves a distance of 250m, the magnitude of the force is
![question image](http://images.topperlearning.com/topper/new-ate/978232Screenshot20200419085357.jpg)
Asked by jahnavibandaru04 | 19 Apr, 2020, 08:57: AM
We know,
Second equation of motion is given as,
s = ut +(1/2) at2
s = 250 m, u = 0, t = 10 s
![S u b s t i t u t i n g space t h e space v a l u e s comma space w e space g e t comma space
250 space equals space 0 space cross times 10 space plus space 1 half cross times a cross times open parentheses 10 close parentheses squared
a space equals space fraction numerator 250 cross times 2 over denominator 100 end fraction space equals space 5 space m divided by s squared space
W e space k n o w comma space
F space equals space m cross times a
m space equals space 0.9 space k g comma space a space space equals space 5 space m divided by s squared
F space space equals space 0.9 space cross times space 5 space equals space 4.5 space N](https://images.topperlearning.com/topper/tinymce/cache/536c6f4c8ebc1149bee96000749272bf.png)
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