JEE Class main Answered
A coil having resistance of 7 ohm and. inductance of 31.8 mH is connected to 230 v, 50hz supply.
calculate 1) The circuit current
2) Phase angle
3) power factor
4) power consumed
Asked by a.muqtadir25 | 23 Mar, 2019, 15:24: PM
Expert Answer
Impedence Z =
Current = V / Z = 230/7.1 = 32.4 A
Phase angle Φ= tan -1 (Lω / R) = tan -1 ( 3.8×10-3 ×2π×50 / 7 ) = tan-1 (0.170) ≈ 9.7 °
power factor = cosΦ = cos (9.7) = 0.986
Power consumed = V × I × cosΦ = 230 × 32.4 × 0.986 = 7348 W
Answered by Thiyagarajan K | 23 Mar, 2019, 17:17: PM
Application Videos
Concept Videos
JEE main - Physics
Asked by sumalathamadarapu9 | 23 Oct, 2024, 22:06: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by py309649 | 13 Oct, 2024, 13:39: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by coolskrish | 13 Oct, 2024, 12:50: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by midnightmoon3355 | 09 Oct, 2024, 09:09: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by rambabunaidu4455 | 03 Oct, 2024, 16:03: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by ratchanavalli07 | 17 Sep, 2024, 07:46: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by yayashvadutta45 | 15 Sep, 2024, 19:47: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by adithireddy999 | 03 Sep, 2024, 09:35: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by vaishalinirmal739 | 29 Aug, 2024, 18:07: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by vradhysyam | 26 Aug, 2024, 17:17: PM
ANSWERED BY EXPERT