CBSE Class 12-science Answered
A bofy at rest of mass 2 kg and charge 5 pC placed inside uniform electric field intensity 4N/C. Find the distance travel by the charge body in 3 sec.
Asked by pradeepjsme | 26 Jun, 2018, 12:09: AM
Expert Answer
Force = q×E = 5×10-12×4 = 20×10-12 N
acceleration = Force / Mass = 20×10-12 / 2000 = 10-10 M/s2
Distance travelled in 3 s starting from rest = (1/2)×a×t2 = (1/2)×10-10×9 = 4.5×10-10 m
Answered by Thiyagarajan K | 26 Jun, 2018, 10:26: AM
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