A bofy at rest of mass 2 kg and charge 5 pC placed inside uniform electric field intensity 4N/C. Find the distance travel by the charge body in 3 sec.

Asked by pradeepjsme | 26th Jun, 2018, 12:09: AM

Expert Answer:

Force = q×E = 5×10-12×4 = 20×10-12 N
 
acceleration = Force / Mass = 20×10-12 / 2000 = 10-10 M/s2
 
Distance travelled in 3 s starting from rest = (1/2)×a×t2 = (1/2)×10-10×9 = 4.5×10-10 m

Answered by Thiyagarajan K | 26th Jun, 2018, 10:26: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.