A body is dropped from a height of 49m. Find the time taken by to reach the ground?

Asked by Sameergandass2407 | 12th Jun, 2019, 10:27: AM

Expert Answer:

As the body is dropped therefore the initial velocity will be 0
u=0
s=49
a=9.8
t=?
 
using 2nd equation of motion
s equals u t plus 1 half a t squared
49 equals 0 plus 1 half cross times 9.8 cross times t squared
t equals square root of 10 equals 3.16 m divided by s

Answered by Utkarsh Lokhande | 12th Jun, 2019, 10:35: AM