ICSE Class 9 Answered
a³-27b³+2a²b - 6ab²
Asked by nagpalmukta510 | 04 Jun, 2020, 09:33: AM
Expert Answer
a³-27b³+2a²b - 6ab²
= a3 - (3b)3 + 2ab(a - 3b)
= (a - 3b)(a2 + (3b)2 + 3ab) + 3ab(a - 3b)
= (a - 3b)(a2 + 9b2 + 3ab + 3ab)
= (a - 3b)(a2 + 9b2 + 6ab)
= (a - 3b)(a + 3b)2
Answered by Renu Varma | 04 Jun, 2020, 09:58: AM
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