ICSE Class 9 Answered
3(log5-log3)-(log5-2log5)=2-logn
Asked by nirmala | 11 Aug, 2013, 09:11: PM
Expert Answer
3(log5-log3)-(log5-2log5)=2-logn
3(log(5/3))-(log(5/5^2))=log100-logn
log(125/27) - log(1/5) = log100 - logn
log (125/27 / 1/5) = log100 - logn
log (625/27) = log100 - logn
logn = log100- log (625/27)
logn = log(100/625/27)
log n = log (108/25)
Hence n = 108/25
Answered by | 12 Aug, 2013, 10:19: PM
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