ICSE Class 10 Answered
1+tanA/sinA + 1+cotA/cosA
Asked by edoc008 | 31 May, 2020, 20:00: PM
(1+tanA)/sinA + (1+cotA)/cosA
= (1 + sinA/cosA)/sinA + (1 + cosA/sinA)/cosA
= (cosA+sinA)/(sinAcosA) + (sinA+cosA)/(sinAcosA)
= 2(sinA+cosA)/(sinAcosA)
= 2/cosA + 2/sinA
Answered by Renu Varma | 31 May, 2020, 21:33: PM
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