1.?Sin8x-cos8x/1-2sin2xcos2x dx is equal to 2.?cos4x+1/cotx-tanx dx=a cos 4x+b,find a

Asked by abhi patel | 16th May, 2012, 09:13: PM

Expert Answer:

We would request you to please ask one question at a time. The solution to your first question is as follows:
 
sin8x-cos8x=(sin4x+cos4x)(sin2x-cos2x)
                   =(1-2sin2xcos2x)(sin2x-cos2x)
 
 
Therefore,
(sin8x-cos8x) / (1-2sin2xcos2x) = sin2x-cos2x
 
Now, you can easily integrate this.

Answered by  | 17th May, 2012, 09:50: AM

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