Question
Wed August 29, 2012 By:

(secA-tanA)^2.(1+sinA)=1-sinA

Expert Reply
Wed August 29, 2012
LHS
= (secA-tanA)^2.(1+sinA)
= (1-sinA)^2.(1+sinA)/ cos^2A
= (1-sinA)^2.(1+sinA)/ (1-sin^2A)
= (1-sinA)^2.(1+sinA)/ (1-sinA)(1+sinA)
= 1-sinA
= RHS
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