Question
Sun December 04, 2011 By:

m,being the mean of x1,x2,x3,x4,x5,x6 find the value of (x1-m)+(x2-m)+(x3-m)+(x4-m)+(x5-m)+(x6-m)

Expert Reply
Mon December 05, 2011
(x1 + x2 + x3 + x4 + x5 + x6)/6 = m
So, (x1 + x2 + x3 + x4 + x5 + x6) = 6m       ---- (i)
Now, (x1 - m) + (x2 - m) + (x3 - m) + (x4 - m) + (x5 - m) + (x6 - m)
= (x1 + x2 + x3 + x4 + x5 + x6) - 6m
= 6m - 6m      (from (i))
= 0
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