Question
Mon July 02, 2012 By:
 

1.84g of a mixture of CaCO3 and MgCO3 is strongly heated till no further loss in mass takes place.The residue is found to weigh 0.96g .calculate the percentage of each component in the mixture.

Expert Reply
Thu July 05, 2012
Let the mass of CaCO3 =xg ,so the mass of MgCO3 = 1.84-xg
x gram of CaCO3 will give CaO = 56 x /100
similarly 1.84 -x g will give MgO = 40(1.84 -x)/ 84 g
Total mass =0.96g
so, 0.56 + 40(1.84 -x)/ 84 g =0.96
x= 1
% of CaCO3 = 1/1.84 = 54.35
% of MgCO3 = 100- 54.35 = 45.65  
 
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